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JEE Main & Advanced JEE Main Paper (Held On 10-Jan-2019 Evening)

  • question_answer
    A particle starts from the origin at time \[t=0\] and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time\[t=5s\]? [JEE Main Online Paper (Held On 10-Jan-2019 Evening]

    A) 3 m                              

    B) 9 m   

    C) 10 m    

    D)                  6 m

    Correct Answer: B

    Solution :

    Area under v-t curve gives displacement. \[A=2+4+3=9=\Delta \,S\] \[\Delta S={{x}_{f}}-{{x}_{i}}=9-0=9\] So, final position is \[x=9\] m.


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