A) 1
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) 2
Correct Answer: A
Solution :
\[F=\frac{2mv}{t}\]\[t=\frac{2l}{v}=\frac{\text{distance}}{\text{velocity}}\] \[t\propto \frac{1}{v}\] \[F\propto {{v}^{2}}\] and \[K.E.\propto T\] \[\frac{1}{2}m{{v}^{2}}\propto T\] \[{{V}^{2}}\propto T\] \[\Rightarrow \] \[F\propto T\]You need to login to perform this action.
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