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JEE Main & Advanced JEE Main Paper (Held on 10-4-2019 Afternoon)

  • question_answer
    If \[\underset{x\to 1}{\mathop{\lim }}\,\frac{{{x}^{2}}-ax+b}{x-1}=5,\] then\[a+b\]is equal to:- [JEE Main 10-4-2019 Afternoon]

    A) -7        

    B) -4

    C) 5                                 

    D) 1

    Correct Answer: A

    Solution :

                \[\underset{x\to 1}{\mathop{\lim }}\,\frac{{{x}^{2}}-ax+b}{x-1}=5\] \[1-a+b=0\]                                        ?(i) \[2-a=5\]                                             ?(ii) \[\Rightarrow a+b=-7.\]        


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