A) \[{{(\sqrt{3}+1)}^{4}}:16\]
B) \[9:1\]
C) \[4:1\]
D) \[25:9\]
Correct Answer: B
Solution :
\[{{I}_{1}}=4{{I}_{0}}\] \[{{I}_{2}}={{I}_{0}}\] \[{{I}_{\max }}={{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}\] \[={{(2\sqrt{{{I}_{0}}}+\sqrt{{{I}_{0}}})}^{2}}=9{{I}_{0}}\] \[{{I}_{\min }}={{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}\] \[={{(2\sqrt{{{I}_{0}}}-\sqrt{{{I}_{0}}})}^{2}}={{I}_{0}}\] \[\therefore \]\[\frac{{{I}_{\max }}}{{{\operatorname{I}}_{\min }}}=\frac{9}{1}\]
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