JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Morning)

  • question_answer
    A copper wire is stretcher! to make it \[0.5\,%\] longer. The percentage change m in its electrical resistance if its volume remain unchanged is: [JEE Main Online Paper (Held On 09-Jan-2019 Morning]

    A) \[0.5\text{ }%\]             

    B) \[2.5\text{ }%\]

    C) \[2.0\text{ }%\]             

    D) \[1.0\text{ }%\]

    Correct Answer: D

    Solution :

    \[R\,\,\,=\,\,\rho \frac{l}{A}\] Al = constant \[\frac{\Delta \,A}{A}+\frac{\Delta \,l}{l}\,\,=\,\,0\] \[100\times \frac{\Delta \,l}{l}\,\,=\,\,0.5\,%\] \[\frac{\Delta \,A}{A}\times \,\,100\,\,=\,-\,0.5\,%\] \[\Rightarrow \,\,\frac{\Delta \,R}{R}\,=\,\frac{\Delta \,l}{l}\,\,-\,\,\frac{\Delta \,A}{A}\] So, \[\frac{\Delta \,R}{R}\,\times \,100\] \[=0.5-\left( -\,0.5 \right)\] \[=1%\] option (d)


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