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JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Evening)

  • question_answer
    If \[x=si{{n}^{-1}}\left( sin\text{ }10 \right)\] and \[y=co{{s}^{-1}}\,\,cos10)\], then \[y-x\] is equal to: [JEE Main Online Paper (Held On 09-Jan-2019 Evening]

    A) 0                                             

    B)               \[7\,\pi \]

    C)               \[\pi \]      

    D)               10

    Correct Answer: C

    Solution :

      \[x=si{{n}^{-1}}\text{ }sin\text{ }10=3\pi -10\] \[y=co{{s}^{-1}}cos\,10=4\pi -10\] \[y-x=\left( 4\pi -10 \right)-(3\pi -10)=\pi \]                        


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