• question_answer If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius '2r' is :   [JEE Main 9-4-2019 Morning] A) $4M$  B)   $M$C) $2M$D) $\frac{M}{2}$

Height of liquid rise in capillary tube $h=\frac{2T\cos {{\theta }_{C}}}{\rho rg}$$\Rightarrow h\propto \frac{1}{r}$ when radius becomes double height become half $\therefore$$h'=\frac{h}{2}$ Now,$M=\pi {{r}^{2}}h\times \rho$and $M'=\pi {{(2r)}^{2}}(h/2)\times \rho =2M$ Option [c]