JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Morning)

  • question_answer If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius '2r' is :   [JEE Main 9-4-2019 Morning]

    A) \[4M\]  

    B)   \[M\]

    C) \[2M\]

    D) \[\frac{M}{2}\]

    Correct Answer: C

    Solution :

     Height of liquid rise in capillary tube \[h=\frac{2T\cos {{\theta }_{C}}}{\rho rg}\]\[\Rightarrow h\propto \frac{1}{r}\] when radius becomes double height become half \[\therefore \]\[h'=\frac{h}{2}\] Now,\[M=\pi {{r}^{2}}h\times \rho \]and \[M'=\pi {{(2r)}^{2}}(h/2)\times \rho =2M\] Option [c]                               


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