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JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Morning)

  • question_answer
    A moving coil galvanometer has resistance \[50\Omega \]and it indicates full deflection at 4mA current. A voltmeter is made using this galvanometer and a \[5k\Omega \]resistance. The maximum voltage, that can be measured using this voltmeter, will be close to : [JEE Main 9-4-2019 Morning]

    A) 10 V                

    B) 20 V

    C) 40 V                

    D) 15 V

    Correct Answer: B

    Solution :

    \[G=50\Omega \]           \[S=5000\Omega \]           \[{{i}_{g}}=4\times {{10}^{-3}}\]           \[V={{i}_{g}}(G+S)\] \[V=4\times {{10}^{3}}\left( 50+5000 \right)\] \[=4\times {{10}^{3}}\left( 5050 \right)\] \[=20.2\text{ }volt\] Option [b]


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