A) \[(1,2)\cup (2,\infty )\]
B) \[(-1,0)\cup (1,2)\cup (3,\infty )\]
C) \[(-1,0)\cup (1,2)\cup (2,\infty )\]
D) \[(-2,-1)\cup (-1,0)\cup (2,\infty )\]
Correct Answer: C
Solution :
\[4-{{x}^{2}}\ne 0;{{x}^{3}}-x>0\] \[x=\pm 2\] \[x(x-1)(x+2)>0\] \[\therefore \]\[{{D}_{f}}\in (-1,0)\cup (1,2)\cup (2,\infty )\]You need to login to perform this action.
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