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JEE Main & Advanced JEE Main Paper (Held on 09-4-2019 Afternoon)

  • question_answer
    If the sum and product of the first three term in an A.P. are 33 and 1155, respectively, then a value of its 11th term is :-                                                             [JEE Main 9-4-2019 Afternoon]

    A) -25

    B) 25

    C) -36                              

    D) -35

    Correct Answer: A

    Solution :

    \[ad+a+a+d=33\Rightarrow a=11\] \[a({{a}^{2}}-{{d}^{2}})=1155\] \[121-{{d}^{2}}=105\] \[{{d}^{2}}=16\Rightarrow d=\pm 4\] If d = 4 then Ist term = 7 If d = -4 then Ist term = 15 \[{{T}_{11}}=7+40=47\] OR   \[{{T}_{11}}=15-40=-25\]                 


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