A) \[7!\]
B) \[5\times 6!\]
C) \[6\times 6!\]
D) \[5\times 7!\]
Correct Answer: B
Solution :
boy and 2 girls in circle \[5!{{\times }^{6}}{{C}_{2}}\times 2!\] \[5!\times \frac{6!}{4!2!}\,\times 2!\] \[5\times 6!\]
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