JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

  • question_answer                 Rate of dehydration of alcohols follows the order:        JEE Main Online Paper (Held On 09 April 2013)         

    A)                 \[{{2}^{0}}>{{1}^{0}}>{{\operatorname{CH}}_{3}}\operatorname{OH}>{{3}^{0}}\]                

    B)                 \[{{3}^{0}}>{{2}^{0}}>{{1}^{0}}{{\operatorname{CH}}_{3}}\operatorname{OH}\]                

    C)                 \[{{2}^{0}}>{{3}^{0}}>{{1}^{0}}{{\operatorname{CH}}_{3}}\operatorname{OH}\]                

    D)                 \[{{\operatorname{CH}}_{3}}\operatorname{OH}>{{1}^{0}}>{{2}^{0}}>{{3}^{0}}\]                

    Correct Answer: B

    Solution :

                    Dehydration of alcohols takes place according to Saytzeff rule. In acid, catalysed dehydration formation of most stable carbocation takes place.                 Thus, the order of dehydration of alcohols is \[{{3}^{0}}>{{2}^{0}}>{{1}^{0}}>C{{H}_{3}}OH\]                

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