[JEE Main Online Paper ( Held On 23 April 2013 )
A) 5.0
B) 2.0
C) 2.5
D) 0.4
Correct Answer: C
Solution :
Quality factor of the circuit \[=\frac{{{\omega }_{0}}}{{{\omega }_{2}}-{{\omega }_{1}}}=\frac{5}{2.5}=2.0\]
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