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JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
                    The sum of the series:             \[{{(2)}^{2}}+2{{(4)}^{2}}+3{{(6)}^{2}}+.....\operatorname{upto}10\operatorname{trems}\operatorname{is}:\]     JEE Main Online Paper ( Held On 23  April 2013 )

    A)                   11300                 

    B)                                          12100

    C)                                          12100 

    D)                                          12300

    Correct Answer: C

    Solution :

                                     \[{{2}^{2}}+2{{(4)}^{2}}+3{{(6)}^{2}}+\]??.up to 10 terms \[={{2}^{2}}[{{1}^{3}}+{{2}^{3}}+{{3}^{3}}+\]......upto 10 terms\[]\] \[=4.{{\left( \frac{10\times 11}{2} \right)}^{2}}=12100\]


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