question_answer

                A parallel plate capacitor of area 60 \[{{\operatorname{cm}}^{2}}\] and separation 3 mm is charged  initially to \[90\mu \operatorname{C}.\] If the medium between the plate gets slightly conducting and the plate loses the charge initially at the rate of \[2.5\times {{10}^{-8}}\operatorname{C}/s,\] then what is the magnetic field between the plates?     JEE Main Online Paper ( Held On 23  April 2013 )

A)                  \[2.5\times {{10}^{-8}}\operatorname{T}\]                        

B)                                         \[2.0\times {{10}^{-7}}\operatorname{T}\]

C)                                         \[1.63\times {{10}^{-11}}\operatorname{T}\]                   

D)                                          Zero