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JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

  • question_answer
                    500 g of water and 100 g of ice at \[{{0}^{0}}\operatorname{C}\]are in a calorimeter whose water equivalent is \[40g.\]\[10\,g\]of  steam at \[{{100}^{0}}C\] is added to it Then water in the calorimeter is : (Latent heat of ice =80 cal/g, Latent heat of stem = 540 cal/g)     [JEE Main Online Paper ( Held On 23  April 2013 )

    A)                   580g                    

    B)                                          590gs

    C)                                          600g                                    

    D)                                          610g

    Correct Answer: B

    Solution :

                      As Ig of steam at 100°C melts 8g of ice at 0°C. 10 g of steam will melt 8x 10 g of ice at 0°C Water in calorimeter = 500 + 80 +1 Og = 590g


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