JEE Main & Advanced JEE Main Paper (Held On 09-Jan-2019 Morning)

  • question_answer
    If the fractional part of the number \[\frac{{{2}^{\,403}}}{15}\] is \[\frac{k}{15}\], then k is equal to: [JEE Main Online Paper (Held On 09-Jan-2019 Morning]

    A) 8     

    B) 14    

    C) 6     

    D) 4

    Correct Answer: A

    Solution :

      \[\frac{{{2}^{403}}}{15}\,\,=\,\,{{2}^{3}}\,\,.\,\,\frac{{{2}^{400}}}{15}\,\,=\,\,\frac{{{2}^{3}}\,.\,({{2}^{4}})\,100}{15}\] \[=\,\,\frac{8{{[1+15]}^{100}}}{15}\] \[=\,\,\,\left\{ \frac{8.1}{15} \right\}\] \[\therefore \,\,k\,\,=\,\,8\]


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