Solved papers for JEE Main & Advanced JEE Main Solved Paper-2016

done JEE Main Solved Paper-2016 Total Questions - 2

• question_answer1) A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up? Fat supplies \[\text{3}.\text{8}\times \text{1}0\text{7J}\]of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 \[m{{s}^{}}^{2}\]:- [JEE Main Solved Paper-2016 ]
  A)
  \[\text{12}.\text{89}\times \text{1}{{0}^{\text{3}}}\text{kg}\]  
  done clear
  B)
  \[\text{2}.\text{45}\times \text{1}{{0}^{\text{3}}}\text{kg}\]
  done clear
  C)
  \[\text{6}.\text{45}\times \text{1}{{0}^{\text{3}}}\text{kg}\]    
  done clear
  D)
  \[\text{9}.\text{89}\times \text{1}{{0}^{\text{3}}}\text{kg}\]
  done clear
  View Answer play_arrow

• question_answer2) A point particle of mass, moves along the uniformly rough track PQR as shown in the figure. The coefficient of friction, between the particle and the rough track equals m. The particle is released, from rest, from the point P and it comes to rest at a point R. The energies, lost by the ball, over the parts, PQ and PR, of the track, are equal to each other, and no energy is lost when particle changes direction from PQ to QR. The values of the coefficient of friction m and the distance x(=QR) are, respecitvely close to :- [JEE Main Solved Paper-2016 ]
  A)
  0.29 and 6.5 m  
  done clear
  B)
  0.2 and 6.5 m
  done clear
  C)
  0.2 and 3.5 m    
  done clear
  D)
   0.29 and 3.5 m
  done clear
  View Answer play_arrow