Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

done JEE Main Paper (Held On 11 April 2015) Total Questions - 1

• question_answer1) A particle is moving in a circle of radius r under the action of a force \[F=\alpha {{r}^{2}}\]which is directed towards centre of the circle. Total mechanical energy (kinetic energy + potential energy) of the particle is (take potential energy=0 for r=0): [JEE Main Online Paper (Held On 11 April 2015)]  
  A)
  \[\alpha {{r}^{3}}\]
  done clear
  B)
  \[\frac{1}{2}\alpha {{r}^{3}}\]
  done clear
  C)
  \[\frac{4}{3}\alpha {{r}^{3}}\]
  done clear
  D)
  \[\frac{5}{6}\alpha {{r}^{3}}\]
  done clear
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