Solved papers for JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

done JEE Main Online Paper (Held On 23 April 2013) Total Questions - 1

• question_answer1)                 A 70 Kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the pushes the ground with a constant force F to raise himself. The center of gravity rises by 0.5 m before he leaps. After the leap the c.g. rises by another 1 m. The maximum power delivered by the muscles is: (Take g=10 \[\text{m}{{\text{s}}^{\text{2}}}\]).     JEE Main Online Paper ( Held On 23  April 2013 )
  A)
                   \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{3}}}\] Watts at the start
  done clear
  B)
                                          \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{3}}}\] Watts at take off
  done clear
  C)
                                          \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{4}}}\] Watts at the start
  done clear
  D)
                                          \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{4}}}\] Watts at take off
  done clear
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