Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

done JEE Main Paper (Held On 9 April 2014) Total Questions - 1

• question_answer1) The equation of state for a gas is given by PV = nRT + aV, where n is the number of moles and a is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are \[{{T}_{o}}\]and \[{{P}_{o}}\]respectively. The work done by the gas when its temperature doubles isobaric ally will be:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )
  A)
  \[\frac{{{P}_{o}}{{T}_{o}}R}{{{P}_{o}}-\alpha }\]
  done clear
  B)
  \[\frac{{{P}_{o}}{{T}_{o}}R}{{{P}_{o}}+\alpha }\]
  done clear
  C)
  \[{{P}_{o}}{{T}_{o}}R\ln 2\]                        
  done clear
  D)
  \[{{P}_{o}}{{T}_{o}}R\]
  done clear
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