Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)
done JEE Main Paper (Held On 9 April 2014)
question_answer1)
An experiment is performed to obtain the value of acceleration due to gravity g by using a simple pendulum of length L. In this experiment time for 100 oscillations is measured by using a watch of 1 second least count and the value is 90.0 seconds. The length L is measured by using a meter scale of least count 1 mm and the value is 20.0 cm. The error in the determination of g would be:
[JEE Main Online Paper ( Held On 09 Apirl 2014 )
Two bodies of masses 1 kg and 4 kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25rad/s, and amplitude 1.6 cm while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is (take \[g=10m{{s}^{-2}}\])
[JEE Main Online Paper ( Held On 09 Apirl 2014 )
The amplitude of a simple pendulum, oscillating in air with a small spherical bob, decreases from 10 cm to 8 cm in 40seconds. Assuming that Stokes law is valid, and ratio of the coefficient of viscosity of air to that of carbon dioxide is 1.3. The time in which amplitude of this pendulum will reduce from 10 cm to 5 cm in carbon dioxide will be close to (In 5 =1.601, In 2 = 0.693).
[JEE Main Online Paper ( Held On 09 Apirl 2014 )
A particle which is simultaneously subjected to two perpendicular simple harmonic motions represented by\[;x={{a}_{1}}\cos \omega t\]and\[y={{a}_{2}}\cos 2\omega t\]traces a curve given by:
[JEE Main Online Paper ( Held On 09 Apirl 2014 )