Solved papers for JEE Main & Advanced JEE Main Paper (Held On 10 April 2016)

done JEE Main Paper (Held On 10 April 2016) Total Questions - 1

• question_answer1) Consider an electromagnetic wave propagating in vacuum. Choose the correct statement :   JEE Main Online Paper (Held On 10 April 2016)
  A)
  For an electromagnetic wave propagating in +y direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( x,t \right)\hat{z}\]and the magnetic field is \[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{z}}\left( x,t \right)\hat{y}\]                
  done clear
  B)
  For an electromagnetic wave propagating in +y direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( x,t \right)\hat{y}\]and he magnetic field is\[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}\left( x,t \right)\hat{z}\]                
  done clear
  C)
  For an electromagnetic wave propagating in +x direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( y,z,t \right)\left( \hat{y}+\hat{z} \right)\]and the magnetic field is\[\overrightarrow{B}=\frac{1}{\sqrt{2}}{{B}_{yz}}\left( y,z,t \right)\left( \hat{y}+\hat{z} \right)\]                
  done clear
  D)
  For an electromagnetic wave propagating in +x direction the electric field is \[\overrightarrow{E}=\frac{1}{\sqrt{2}}{{E}_{yz}}\left( x,t \right)\left( \hat{y}-\hat{z} \right)\]and eh magnetic field is \[B=\frac{1}{\sqrt{2}}{{B}_{yz}}\left( x,t \right)\left( \hat{y}+\hat{z} \right)\]                
  done clear
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