# Solved papers for JEE Main & Advanced JEE Main Solved Paper-2016

### done JEE Main Solved Paper-2016

• question_answer1) A combination of capacitors is set up as shown in the figure. The magnitude of the electric field, due to a point charge Q (having a charge equal to the sum of the charges on the $4\mu F$ and $9\mu F$capacitors), at a point 30 m from it , would equal: [JEE Main Solved Paper-2016 ]

A)  480 N/C

B) 240 N/C

C) 360 N/C

D) 420 N/C

• question_answer2) The region between two concentric spheres of radii 'a' and 'b', respectively (see figure), has volume charge density $\rho =\frac{A}{r},$where A is a constant and r is the distance from the centre. At the centre of the spheres is a point charge Q. The value of A such that the electric field in the region between the spheres will be constant, is :- [JEE Main Solved Paper-2016 ]

A) $\frac{2Q}{\pi {{a}^{2}}}$

B) $\frac{Q}{2\pi {{a}^{2}}}$

C) $\frac{Q}{2\pi ({{b}^{2}}-{{a}^{2}})}$

D) $\frac{2Q}{\pi ({{a}^{2}}-{{b}^{2}})}$

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