Solved papers for JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)

done JEE Main Paper (Held On 25 April 2013) Total Questions - 3

• question_answer1)                 This question has Statement-1 and that Statements-2. Of the four choice given after the Statements, choose the one that best describes the two Statements.                 Statement 1: No work is required to be done to move a fest charge between any two pints on an equipotential surface.                 Statement 2: Electric lines of force at the equipotential surfaces are mutually perpendicular to each other     JEE Main Online Paper ( Held On 25  April 2013 )
  A)
                  Statement 1 is true, Statement 2 is true, Statement 2 is the correct explanation of Statement 1
  done clear
  B)
                                         Statement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation of Statement 1.
  done clear
  C)
                                         Statement 1 is true, Statement 2 is false.
  done clear
  D)
                                         Statement 1 is false, Statement 2 is true.
  done clear
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• question_answer2) The surface charge density of a thin charge disc of radius R is \[\sigma \]. The value of the electric field at the centre of the disc is \[\frac{\sigma }{2{{\in }_{0}}}.\]With respect to the field at the centre, the electric field along the axis at a distance R From the centre of the disc:     JEE Main Online Paper ( Held On 25  April 2013 )
  A)
  reduces by 70.7%      
  done clear
  B)
  reduces by 29.3%
  done clear
  C)
  reduces by 9.7%              
  done clear
  D)
  reduces by 14.6%
  done clear
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• question_answer3)                 A parallel plate capacitor having a separation between the plates d, plate area A and material with dielectric constant K has capacitance \[{{C}_{0}}\]. Now one-third of the materialism replaced by another material with dielectric constant 2K, so that effectively there are two capacitors one with area \[\frac{1}{3}\operatorname{A},\] dielectric constant 2 K and another with area \[\frac{2}{3}\operatorname{A},\]and dielectric constant K. If the capacitance of this new capacitor is C then \[C/{{C}_{0}}\]is:     JEE Main Online Paper ( Held On 25  April 2013 )
  A)
                  \[1\]                                     
  done clear
  B)
                                         \[\frac{4}{3}\]
  done clear
  C)
                                         \[\frac{2}{3}\]                                   
  done clear
  D)
                                         \[\frac{1}{3}\]
  done clear
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