Solved papers for JEE Main & Advanced AIEEE Solved Paper-2005

done AIEEE Solved Paper-2005 Total Questions - 8

• question_answer1) A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 V, the resistance in Ohm's needed to be connected in series with the coil will be     AIEEE  Solved  Paper-2005
  A)
  \[{{10}^{3}}\] 
  done clear
  B)
                                         \[{{10}^{5}}\]                    
  done clear
  C)
         99995                   
  done clear
  D)
         9995
  done clear
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• question_answer2) Two voltameters, one of copper and another of silver, are joined in parallel. When a total charge q flows through the voltameters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are\[{{z}_{1}}\]and\[{{z}_{2}}\]respectively, the charge which flows through the silver voltameter is     AIEEE  Solved  Paper-2005
  A)
  \[\frac{q}{1+\frac{{{z}_{1}}}{{{z}_{2}}}}\]  
  done clear
  B)
                                         \[\frac{q}{1+\frac{{{z}_{2}}}{{{z}_{1}}}}\]             
  done clear
  C)
         \[q\frac{{{z}_{1}}}{{{z}_{2}}}\]                   
  done clear
  D)
         \[q\frac{{{z}_{2}}}{{{z}_{1}}}\]
  done clear
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• question_answer3) In the circuit, the galvanometer G shows zero deflection. If the batteries A and B have negligible internal resistance, the value of the resistor R will be   AIEEE  Solved  Paper-2005
  A)
  \[200\,\Omega \]     
  done clear
  B)
        \[100\,\Omega \]            
  done clear
  C)
         \[500\,\Omega \]           
  done clear
  D)
         \[1000\,\Omega \]
  done clear
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• question_answer4) Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are\[{{R}_{1}}\]and\[{{R}_{2}}({{R}_{2}}>{{R}_{1}})\].   If   the   potential difference across the source having internal resistance\[{{R}_{2}}\]is zero, then     AIEEE  Solved  Paper-2005
  A)
  \[R=\frac{{{R}_{2}}({{R}_{1}}+{{R}_{2}})}{({{R}_{2}}-{{R}_{1}})}\]               
  done clear
  B)
  \[R={{R}_{2}}-{{R}_{1}}\]             
  done clear
  C)
         \[R=\frac{{{R}_{1}}{{R}_{2}}}{({{R}_{1}}+{{R}_{2}})}\]     
  done clear
  D)
  \[R=\frac{{{R}_{1}}{{R}_{2}}}{({{R}_{2}}-{{R}_{1}})}\]
  done clear
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• question_answer5) A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be     AIEEE  Solved  Paper-2005
  A)
  doubled   
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  B)
                         four times          
  done clear
  C)
         one-fourth        
  done clear
  D)
         halved
  done clear
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• question_answer6) An energy source will supply a constant current into the load, if its internal resistance is     AIEEE  Solved  Paper-2005
  A)
  equal to the resistance of the load
  done clear
  B)
  very large as compared to the load resistance
  done clear
  C)
  zero
  done clear
  D)
  non-zero but less than the resistance of the load
  done clear
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• question_answer7) In a potentiometer experiment, the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of Q, the balancing length becomes 120 cm. The internal resistance of the cell is     AIEEE  Solved  Paper-2005
  A)
  \[1\,\Omega \]  
  done clear
  B)
                         \[0.5\,\Omega \]             
  done clear
  C)
         \[4\,\Omega \]                
  done clear
  D)
         \[2\,\Omega \]
  done clear
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• question_answer8) The resistance of hot tungsten filament is about 10 times the cold resistance. What will be the resistance of 100 W and 200 V lamp, when not in use?     AIEEE  Solved  Paper-2005
  A)
  \[40\,\Omega \]
  done clear
  B)
                                         \[20\,\Omega \]              
  done clear
  C)
         \[400\,\Omega \]            
  done clear
  D)
         \[200\,\Omega \]
  done clear
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