Solved papers for JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

done JEE Main Online Paper (Held on 9 April 2013) Total Questions - 1

• question_answer1)                 In the Bohr model an electron moves in a circular orbit around the proton. Considering the orbiting electron to be a circular current loop, the magnetic moment of the hydrogen atom, when the electron is in \[{{\operatorname{n}}^{\operatorname{th}}}\] exited state, is:             JEE Main Online Paper (Held On 09 April 2013)      
  A)
                  \[\left( \frac{e}{2m} \right)\frac{{{\operatorname{n}}^{2}}h}{2\pi }\]                
  done clear
  B)
                  \[\left( \frac{e}{m} \right)\frac{\operatorname{n}h}{2\pi }\]                
  done clear
  C)
                  \[\left( \frac{e}{2m} \right)\frac{\operatorname{n}h}{2\pi }\]                
  done clear
  D)
                  \[\left( \frac{e}{m} \right)\frac{{{\operatorname{n}}^{2}}h}{2\pi }\]                
  done clear
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