Solved papers for JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

done JEE Main Paper (Held On 19 April 2014)

  • question_answer1) The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points \[({{a}^{2}}+1,{{a}^{2}}+1)\]and \[(2a,-2a),a\ne 0.\]Then for any a, the orthocentre of this triangle lies on the line:     JEE Main Online Paper (Held On 19 April 2016)

    A) \[y-2ax=0\]                        

    B) \[y-({{a}^{2}}+1)x=0\]

    C) \[y+x=0\]                           

    D) \[{{(a-1)}^{2}}x-{{(a+1)}^{2}}y=0\]

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JEE Main Online Paper (Held On 19 April 2014)
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