# Solved papers for JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

### done JEE Main Paper (Held On 19 April 2014)

• question_answer1) The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points $({{a}^{2}}+1,{{a}^{2}}+1)$and $(2a,-2a),a\ne 0.$Then for any a, the orthocentre of this triangle lies on the line:     JEE Main Online Paper (Held On 19 April 2016)

A) $y-2ax=0$

B) $y-({{a}^{2}}+1)x=0$

C) $y+x=0$

D) ${{(a-1)}^{2}}x-{{(a+1)}^{2}}y=0$