Solved papers for JEE Main & Advanced AIEEE Solved Paper-2013

done AIEEE Solved Paper-2013 Total Questions - 1

• question_answer1) ABCD is a trapezium such that AB and CD are parallel and\[BC\bot CD\]. If\[\angle ADB=\theta ,\text{ }BC=p\] and\[CD=q,\]then AB is equal to:     AIEEE Solevd Paper-2013
  A)
  \[\frac{({{p}^{2}}\text{+}{{q}^{2}})sin\theta }{p\,cos\,\theta +q\,sin\,\theta }\]
  done clear
  B)
         \[\frac{{{p}^{2}}+{{q}^{2}}cos}{p\,cos\,\theta +q\,sin\,\theta }\]
  done clear
  C)
  \[\frac{{{p}^{2}}+{{q}^{2}}}{{{p}^{2}}cos\,\theta +{{q}^{2}}sin\,\theta }\]
  done clear
  D)
         \[\frac{({{p}^{2}}+{{q}^{2}})\sin \theta }{{{(pcos\,\theta +qsin\,\theta )}^{2}}}\]
  done clear
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