Solved papers for JEE Main & Advanced JEE Main Paper (Held On 10 April 2015)

done JEE Main Paper (Held On 10 April 2015) Total Questions - 1

• question_answer1) If \[f(x)=2ta{{n}^{-1}}x+{{\sin }^{-1}}\left( \frac{2x}{1+{{x}^{2}}} \right),x>1,\]then f(5) is equal to : JEE Main Online Paper (Held On 10 April 2015)
  A)
  \[\frac{\pi }{2}\]                                              
  done clear
  B)
  \[\pi \]
  done clear
  C)
  \[{{\tan }^{-1}}\left( \frac{65}{156} \right)\]                        
  done clear
  D)
  \[4{{\tan }^{-1}}(5)\]
  done clear
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