Solved papers for JEE Main & Advanced JEE Main Solved Paper-2014

done JEE Main Solved Paper-2014 Total Questions - 1

• question_answer1) The locus of the foot of perpendicular drawn from the centre of the ellipse \[{{x}^{2}}+3{{y}^{2}}=6\] on any tangent to it is :   JEE Main  Solved  Paper-2014
  A)
  \[{{({{x}^{2}}-{{y}^{2}})}^{2}}=6{{x}^{2}}+2{{y}^{2}}\]
  done clear
  B)
  \[{{({{x}^{2}}-{{y}^{2}})}^{2}}=6{{x}^{2}}-2{{y}^{2}}\]
  done clear
  C)
  \[{{({{x}^{2}}+{{y}^{2}})}^{2}}=6{{x}^{2}}+2{{y}^{2}}\]
  done clear
  D)
  \[{{({{x}^{2}}+{{y}^{2}})}^{2}}=6{{x}^{2}}-2{{y}^{2}}\]
  done clear
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