Solved papers for JEE Main & Advanced AIEEE Solved Paper-2003

done AIEEE Solved Paper-2003 Total Questions - 1

• question_answer1) If \[f(x)=\left\{ \begin{matrix}    x{{e}^{-\left[ \frac{1}{\left| x \right|}+\frac{1}{x} \right]}} & ,x\ne 0  \\    0 & ,x=0  \\ \end{matrix} \right.\] , then f(x) is     AIEEE  Solved  Paper-2003
  A)
  continuous as well as differentiable for all x
  done clear
  B)
  continuous for all x but not differentiable at \[x=0\]
  done clear
  C)
  neither differentiable nor continuous at \[x=0\]
  done clear
  D)
  discontinuous everywhere
  done clear
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