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JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    A particle moves along a straight line OX. At a time t (in second) the distance x of the particle from O is given by \[x=40+12t-{{t}^{3}}.\] How long would the particle travel before coming to  rest?

    A)  24 m   

    B)  40 m   

    C)  56 m    

    D)  16 m

    Correct Answer: C

    Solution :

     Distance travelled by the particle is \[x=40+12t-{{t}^{3}}\] \[v=\frac{dx}{dt}=12-3{{t}^{2}}\] But final velocity \[v=0\] \[12-3{{t}^{2}}=0\] \[{{t}^{2}}=\frac{12}{3}=4\] \[t=2S\] \[x=40+12(2)-8\] \[=56\,m\]


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