A) \[S<Se<Cl\]
B) \[Se<S<Cl\]
C) \[Cl<S<Se\]
D) \[Se=S<Cl\]
Correct Answer: B
Solution :
lonisation energy generally increase from left to right across a row of the Periodic Table and decreases from top to bottom down a group. Hence, IE of CI > S and IE of Se < S. Thus, the order is Se < S < Cl.
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