A) \[0{{\,}^{o}}C\]
B) \[-10{{\,}^{o}}C\]
C) \[10{{\,}^{o}}C\]
D) \[40{{\,}^{o}}C\]
Correct Answer: B
Solution :
Temperature gradient \[=\frac{{{\theta }_{1}}-{{\theta }_{2}}}{l}\] Here, \[{{\theta }_{1}}=30{{\,}^{o}}C\] \[l=0.5\,m\] \[\therefore \] \[80=\frac{30-{{\theta }_{2}}}{0.5}\] \[{{\theta }_{2}}=30-80\times 0.5\] \[\Rightarrow \] \[{{\theta }_{2}}=30-40=-10{{\,}^{o}}C\]
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