JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    When an electron in hydrogen atom is excited from its 4th to 5th stationary orbit, the change   in  angular momentum  of electron  is (Plancks constant \[h=6.6\times {{10}^{-34}}\,Js\])

    A) \[4.16\times {{10}^{-34}}Js\]

    B)  \[3.32\times {{10}^{-34}}Js\]

    C)  \[1.05\times {{10}^{-34}}Js\]

    D) \[2.08\times {{10}^{-34}}Js\]

    Correct Answer: C

    Solution :

     \[{{L}_{5}}-{{L}_{4}}\frac{5h}{2\pi }-\frac{4h}{2\pi }\] \[=\frac{h}{2\pi }\] \[=\frac{6.6\times {{10}^{-34}}}{2\times 3.14}\] \[=1.05\times {{10}^{-34}}Js\]


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