A) \[{{P}_{2}}{{O}_{5}}\]
B) \[Mn{{O}_{2}}\]
C) \[M{{n}_{2}}{{O}_{7}}\]
D) \[{{P}_{2}}{{O}_{3}}\]
Correct Answer: D
Solution :
According to Fajans rule compounds having large charge on cation are more covalent or least electrovalent. So, compounds having low charge on cation will be more electrovalent or ionic. \[\overset{\text{+}\,\text{4}}{\mathop{\text{M}}}\,\text{n}{{\text{O}}_{\text{2}}}\] \[\overset{\text{+}\,7}{\mathop{\text{M}}}\,{{\text{n}}_{2}}{{\text{O}}_{7}}\] \[{{\overset{\text{+}\,5}{\mathop{\text{M}}}\,}_{2}}{{\text{O}}_{5}}\] \[{{\overset{\text{+}\,\text{3}}{\mathop{\text{P}}}\,}_{\text{2}}}{{\text{O}}_{\text{3}}}\] So, \[{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]will be most ionic.You need to login to perform this action.
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