question_answer

The force on a conductor of length I placed in a magnetic field of magnitude B and carrying a current\[i\]is given by (\[\theta \]is the angle, the conductor makes with the direction of B):

A) \[F=i\,lB\sin \theta \]

B)  \[F={{i}^{2}}l{{B}^{2}}\sin \theta \]

C)  \[F=i\,l\,B\,\cos \theta \]

D)  \[F=\frac{{{i}^{2}}l}{B}\sin \theta \]

Correct Answer: A

Solution :

The general equation for the force acting on a current carrying conductor placed in a magnetic field [B] is given by Note: The expression can also be obtained from Lorentz force equation.