A) octahedral
B) tetrahedral
C) trigonal bipyramidal
D) square planar
Correct Answer: C
Solution :
Key Idea: Write the name of orbitals which are participating in bond formation and then calculate percentage.Hybridisation | Orbitals | % of s character |
Octahedral | \[s{{p}^{3}}{{d}^{2}}\] | 16.7% |
Tetrahedral | \[s{{p}^{3}}\] | 25% |
Trigonal bipyramidal | \[s{{p}^{3}}d\] | 20% |
Square planar | \[s{{p}^{3}}{{d}^{2}}\] | 16.7% |
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