JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    The temperature at which the mean \[KE\] of the molecules of gas is one-third of the mean \[KE\] of its molecules at \[{{180}^{o}}C\] is

    A) \[-{{122}^{o}}C\]                             

    B) \[-{{90}^{o}}C\]

    C) \[{{60}^{o}}C\]                 

    D)  \[{{151}^{o}}C\]

    Correct Answer: D

    Solution :

    Kinetic energy of a gas is directly proportional to its temperature \[\therefore \]                  \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\]                 \[\frac{K}{K/3}=\frac{273+180}{{{T}_{2}}}\Rightarrow 3=\frac{453}{{{T}_{2}}}\]                 \[{{T}_{2}}={{151}^{o}}C\]


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