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JCECE Engineering JCECE Engineering Solved Paper-2014

  • question_answer
    \[50\,\,mL\] of \[1\,\,M\] oxalic acid (molar mass\[=126\]) is shaken with \[0.5\,\,g\] of wood charcoal. The final concentration of the solution after adsorption is\[0.5\,\,M\]. What is the amount of oxalic acid adsorbed per gram of carbon?

    A) \[3.15\]                               

    B) \[1.575\]

    C) \[6.30\]                               

    D) \[12.60\]

    Correct Answer: C

    Solution :

    Weight of \[50\,\,mL\] \[\text{of}\,\,1\,\,M\] oxalic-acid                 \[w=\frac{NEV}{1000}\]                       \[(\text{Here},\,\,N=m)\]                     \[=\frac{1\times 126\times 50}{1000}\]                     \[=6.3\,\,g\] Similarly weight of 50 ml of Q.5 M oxalic acid                      \[=\frac{0.5\times 126\times 50}{1000}\]                      \[=3.15\,\,g\] Adsorbed oxalic acid on \[0.5\,\,g\]charcoal\[=6:3-3.15=3.15g\] Amount of oxalic acid adsorbed per gram of charcoal                 \[=\frac{3.15}{0.5}=6.3\]


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