A)
has a minimum value
B) has a maximum value\[2\]
C) is continuous in\[\left[ 0,\,\,\frac{\pi }{2} \right]\]
D) is not differentiable at\[x=\frac{\pi }{2}\]
Correct Answer: C
Solution :
Since,\[f(x)=1\]in\[0<x<\frac{\pi }{2}\](as\[[\cos x]=0\]) \[\therefore \,\,f(x)\]is continuous in\[\left[ 0,\,\,\frac{\pi }{2} \right]\].
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