A) \[\frac{1}{2}\]
B) \[\frac{11}{25}\]
C) \[\frac{19}{50}\]
D) None of these
Correct Answer: C
Solution :
We have, probability of \[A\] to fail \[P(A)=\frac{1}{5}\Rightarrow P(\bar{A})=\frac{4}{5}\] Similarly,\[P(B)=\frac{3}{10}\Rightarrow P(\bar{B})=\frac{7}{10}\] Probability that either \[A\] or \[B\] fails is \[=P(A)P(\bar{B})+P(\bar{A})P(B)\] \[=\frac{1}{5}\cdot \frac{7}{10}+\frac{4}{5}\cdot \frac{5}{10}=\frac{19}{50}\]You need to login to perform this action.
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