JCECE Engineering JCECE Engineering Solved Paper-2010

  • question_answer
    A wheel completes \[2000\] revolutions to cover the \[9.5\,\,km\] distance, then the diameter of the wheel is

    A) \[1.5\,\,m\]                       

    B) \[1.5\,\,cm\]

    C)  \[7.5\,\,cm\]                    

    D)  \[7.5\,\,m\]

    Correct Answer: A

    Solution :

    Distance covered in \[n\] revolution\[=n2\pi r=n\pi l)\] \[\Rightarrow \]               \[2000\pi D=9500\]                 [As\[n=2000\]distance\[=9500\,\,m]\] \[\Rightarrow \]               \[D=\frac{9500}{2000\times \pi }=1.5\,\,m\]


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