A) \[{{C}_{2}}{{H}_{5}}OH\]
B) \[C{{H}_{3}}OC{{H}_{3}}\]
C) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]
D) \[C{{H}_{3}}O{{C}_{2}}{{H}_{5}}\]
Correct Answer: C
Solution :
Diethyl ether when heated with \[CO\] at \[{{150}^{o}}C\] and 500 aim pressure in presence of \[B{{F}_{3}}\] forms ethyl propionate. \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+CO\xrightarrow[500\,\,atm]{{{150}^{o}}C\,\,\Delta }\underset{ethyl\,\,propionate}{\mathop{{{C}_{2}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}}}\,\]
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