question_answer

In this reaction\[C{{H}_{3}}CHO+HCN\xrightarrow{{}}C{{H}_{3}}CH(OH)CN\]       \[\xrightarrow{H\cdot OH}C{{H}_{3}}CH(OH)COOH\]an asymmetric centre is generated. The acid obtained would be

A)  \[50%\,\,D+50%\,\,L\text{-}\]isomer

B)  \[20%\,\,D+80%\,\,L\text{-}\]isomer

C)  \[D-\]isomer

D)   \[L-\]isomer

Correct Answer: A

Solution :

Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exists as d and; forms whose ratio is\[1:1\].