JCECE Engineering JCECE Engineering Solved Paper-2007

  • question_answer
    The least number of times a fair coin must be tossed so that the probability of getting at least one head in at least \[0.8\] is:

    A) \[3\]                                     

    B) \[6\]

    C) \[5\]                                     

    D)  none of these

    Correct Answer: A

    Solution :

    Suppose the coin is tossed \[n\] times. Let \[x\] be the number of heads obtained. Then \[x\] follows a binomial distribution with parameters \[n\] and \[p=\frac{1}{2}\] , we have                 \[p(x\ge 1)\ge 0.8\Rightarrow 1-P(x=0)\ge 0.8\] \[\Rightarrow \]               \[P(x=0)\le 1-0.8=0.2\] \[\Rightarrow \]               \[^{n}{{C}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\le 0.2=\frac{2}{10}=\frac{1}{5}\] \[\Rightarrow \]               \[{{\left( \frac{1}{2} \right)}^{n}}\le \frac{1}{5}\Rightarrow {{2}^{n}}\le 5\] \[\therefore \] Least value of\[n\]is\[3\].


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