A) \[\pi /4\]
B) \[3\pi /5\]
C) \[\pi /6\]
D) \[\pi /2\]
Correct Answer: C
Solution :
The phase of particle at \[t=3\,\,s\] is \[{{\phi }_{1}}=\omega t=\left( \frac{2\pi }{T} \right)t\] \[=\frac{2\pi \times 3}{12}=\frac{\pi }{2}\] At\[t=4\,\,s\] \[{{\phi }_{2}}=\omega t=\left( \frac{2\pi }{T} \right)t\] \[=\frac{2\pi \times 4}{12}=\frac{2\pi }{3}\] Phase difference \[\Delta \phi ={{\phi }_{2}}-{{\phi }_{1}}=\frac{2\pi }{3}-\frac{\pi }{2}=\frac{\pi }{6}\]
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