A) \[p=1\]or\[0\]
B) \[p=-2\]or\[0\]
C) \[p=-2\]
D) \[p=1\]
Correct Answer: A
Solution :
Since, \[p\] and \[q\] are the roots of the equation \[{{x}^{2}}+px+q=0\] \[\therefore \] \[p+q=-p\]and\[pq=q\] \[\Rightarrow \] \[2p+q=0\]and\[q(p-1)=0\] If \[q=0,\] then\[p=0\] If \[p=1,\]then\[q=-2\] \[\therefore \] \[p=1\]or\[0\]You need to login to perform this action.
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