A) \[190\,\,MeV\]
B) \[931\,\,MeV\]
C) \[93.1\,\,MeV\]
D) \[931\,\,J\]
Correct Answer: B
Solution :
Key Idea: Mass of \[1\] proton\[=1\,\,amu\] \[=1.66\times {{10}^{-27}}kg\] \[\therefore \]energy equivalent to\[1\,\,amu=m{{c}^{2}}\] where \[m=\] mass of proton\[=1.66\times {{10}^{-27}}kg\] \[c=\]velocity of light\[=2.98\times {{10}^{8}}m{{s}^{-1}}\] \[\therefore \] \[E=1.66\times {{10}^{-27}}\times {{(2.98\times {{10}^{8}})}^{2}}\] \[=1.4925\times {{10}^{-10}}J\] \[=931.65\,\,MeV(\because \,\,1eV=1.602\times {{10}^{-19}}J)\] \[\approx 931\,\,MeV\]
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